document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=452389>Question 452389</A>: <I><SPAN STYLE=\"word-break: break-all;\"> My grandaughter came home with six of these math problems (6th grade)....\r<BR>\n" );
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document.write( "Using the numbers (2,3,4,5,7,8,9) fill in the blanks.<BR>\n" );
document.write( " _*_-_/_+_*_/_=3\r<BR>\n" );
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document.write( "Using brute force it took me (and four other ADULTS) several hours to answer all 6 questions....<BR>\n" );
document.write( "Am I missing something here?? Is there some technique I am missing? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #311036 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=311036\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> It is impossible to obtain 3 using all the digits once, assuming the order of operations is followed.\r<BR>\n" );
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document.write( "Suppose the integers are a,b,...g in that order, with\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE ab - \frac{c}{d} + \frac{ef}{g} = 3\">\r<BR>\n" );
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document.write( "This implies \r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE ab + \frac{ef}{g} = 3 + \frac{c}{d}\">\r<BR>\n" );
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document.write( "The maximum value the RHS can attain is when c = 9, d = 2, in which RHS = 15/2. If this is the case, ab must be greater than or equal to 3*4 = 12, in which this is impossible. In all other cases, the maximum value of the RHS is smaller than the minimum value of the LHS, implying that equality is impossible to obtain.\r<BR>\n" );
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