document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=450482>Question 450482</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the domain of the square-root function: y = &#8730; 2(x+4) - 3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #311033 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=311033\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the domain of the square-root function: y = &#8730; 2(x+4) - 3<BR>\n" );
document.write( "..<BR>\n" );
document.write( "y = &#8730; 2(x+4) - 3<BR>\n" );
document.write( "What is inside a sqrt must be &#8805;0<BR>\n" );
document.write( "Assuming 2(x+4) is inside the sqrt<BR>\n" );
document.write( "2(x+4)&#8805;0<BR>\n" );
document.write( "2x+8&#8805;0<BR>\n" );
document.write( "2x&#8805;-8<BR>\n" );
document.write( "x&#8805;-4<BR>\n" );
document.write( "or<BR>\n" );
document.write( "[-4,&#8734;) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );