document.write( "Question 5738: A crew of 6 men can complete the construction of an office in 60 days. In order to speed up the job the contractor increases the size of the crew by 1/3. How many days will he save by the addition of these men? \n" ); document.write( "
Algebra.Com's Answer #3110 by Abbey(339)![]() ![]() ![]() You can put this solution on YOUR website! if the crew can do the job in 60 days, then each day, 1/60th of the job is complete. \n" ); document.write( "each of the 6 men are performing 1/6th of the 1/60th of the work, or 1/360th of the work. \n" ); document.write( "so if the crew is increased by 2 men (1/3 of 6 = 2), they are collectively performing 8/360th of the work.\r \n" ); document.write( "\n" ); document.write( "if we divide 360 by 8, the result is 45 days. \r \n" ); document.write( "\n" ); document.write( "The original construction was going to take 60 days, now it will take 45 days, so the amount of time saved will be 60-45 or 15 days. \n" ); document.write( " |