document.write( "Question 452318: Factor x^3-8\r
\n" ); document.write( "\n" ); document.write( "I got the answer (x-2)(x^+2x+4) but I don't know how\r
\n" ); document.write( "\n" ); document.write( "Please show me step by step to get the answer. Thanks \n" ); document.write( "
Algebra.Com's Answer #310981 by confusedgirl81(14)\"\" \"About 
You can put this solution on YOUR website!
First this is to understand Quadratic is all bout the finding the zero's.\r
\n" ); document.write( "\n" ); document.write( "so x^3 - 8 = 0
\n" ); document.write( "x^3 = 8
\n" ); document.write( "x = 2
\n" ); document.write( "We can use The Difference of Two Cubes Formula to solve this.\r
\n" ); document.write( "\n" ); document.write( "The formula says a^3 - b^3. If we factor (a - b) out we will get (a - b)(a^2 + ab + b^2).\r
\n" ); document.write( "\n" ); document.write( "So lets put your info in the formula. \r
\n" ); document.write( "\n" ); document.write( "let a = x and b = 2\r
\n" ); document.write( "\n" ); document.write( "x^3 - 2^3\r
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\n" ); document.write( "\n" ); document.write( "Now factor x-2 out and we are left with (x-2)(x^2 + 2x + 2^2)\r
\n" ); document.write( "\n" ); document.write( "So x^3 - 8 = x^3 - 2^3 = (x-2)(x^2 + 2x + 2^2)\r
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\n" ); document.write( "\n" ); document.write( "If you need more help, just ask! \r
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