document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=452348>Question 452348</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Trains A and B are traveling the same direction on parrarel lines. Train A is traveling 100 mph and train B is traveling 120 mph. Train A passes the station at 5:25 am and train B passes station at 5:37 am, what time will train B catch up with train A? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #310980 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=310980\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Trains A and B are traveling the same direction on parrarel lines. Train A is traveling 100 mph and train B is traveling 120 mph. Train A passes the station at 5:25 am and train B passes station at 5:37 am, what time will train B catch up with train A?<BR>\n" );
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document.write( "The relative speed of the two trains is 120 - 100 = 20 mph<BR>\n" );
document.write( "Train A has a 12 min. head start. In that time train A traveled 100 mph * 1/5 hr = 20 miles<BR>\n" );
document.write( "Since the relative speed is 20 mph, if train A were standing still train B would <BR>\n" );
document.write( "approach train A at 20 mph.  The time required to travel 20 miles at 20 mph is:<BR>\n" );
document.write( "20 mi/20 mi/hr = 1 hr.<BR>\n" );
document.write( "So they meet at 6:37 am </SPAN>\n" );
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