document.write( "Question 452357: how many pounds of salted nuts selling for $1.40 per pound should be mixed with 7 pounds of salted nuts selling for $2.40 per pound to obtain a mixture selling for $2.10 per pound ? \n" ); document.write( "

Algebra.Com's Answer #310977 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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how many pounds of salted nuts selling for $1.40 per pound should be mixed with 7
\n" ); document.write( " pounds of salted nuts selling for $2.40 per pound to obtain a mixture selling for $2.10 per pound?
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\n" ); document.write( "Let x = amt of $1.40 nuts required
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\n" ); document.write( "A typical mixture equation
\n" ); document.write( "1.40x + 2.40(7) = 2.10(x+7)
\n" ); document.write( "1.4x + 16.8 = 2.1x + 14.7
\n" ); document.write( "16.8 - 14.7 = 2.1x - 1.4x
\n" ); document.write( "2.1 = .7x
\n" ); document.write( "x = $\"2.1%2F.7\"$
\n" ); document.write( "x = 3 lb of $1.40 nuts required
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\n" ); document.write( "Check this out in the original mixture equation
\n" ); document.write( "1.4(3) + 2.4(7) = 2.1(3+7)
\n" ); document.write( "4.2 + 16.8 = 21
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