document.write( "Question 452313: Soybean meal is 14% protein; cornmeal is 7% protein. How many pounds of each should be mixed together in order to get 280lb mixture that is 13% protein?
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document.write( "How many pounds of the cornmeal should be in mixture?
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document.write( "How many pounds of the soybean meal should be in mixture?\r
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document.write( "Thank you,
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document.write( "Missy \n" );
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Algebra.Com's Answer #310967 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Soybean meal is 14% protein; cornmeal is 7% protein. \n" ); document.write( " How many pounds of each should be mixed together in order to get 280lb mixture that is 13% protein? \n" ); document.write( "How many pounds of the cornmeal should be in mixture? \n" ); document.write( "How many pounds of the soybean meal should be in mixture? \n" ); document.write( ": \n" ); document.write( "Let s = amt of soy \n" ); document.write( "Let c = amt of corn \n" ); document.write( ": \n" ); document.write( "Write two equations, one for total amt, another for percent protein \n" ); document.write( ": \n" ); document.write( "s + c = 280 \n" ); document.write( "c = (280-s); use this form for substitution \n" ); document.write( "and \n" ); document.write( ".14s + .07c = .13(280) \n" ); document.write( "replace c with (280-s) \n" ); document.write( ".14s + .07(280-s) = 36.4 \n" ); document.write( ".14s + 19.6 - .07s = 36.3 \n" ); document.write( ".14s - .07s = 36.4 - 19.6 \n" ); document.write( ".07s = 16.8 \n" ); document.write( "s = \n" ); document.write( "s = 240 lb of soy required \n" ); document.write( "then \n" ); document.write( "280 - 240 = 40 lb of corn required \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "See if that checks out: \n" ); document.write( ".14(240) + .07(40) = .13(280) \n" ); document.write( "33.6 + 2.8 = 36.4; confirm our solutions \n" ); document.write( " |