document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=46943>Question 46943</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can someone help me please??...<BR>\n" );
document.write( "the question asks to solve the eqaution for x<BR>\n" );
document.write( "log(bottom side 3) 1/81 = x\r<BR>\n" );
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document.write( "can someone show me how to do this? thanks!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #31089 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=31089\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Okay, we exponentiate both sides...as in \"3 to the\"...since it is to the base three...we get<BR>\n" );
document.write( "log(bottom side 3) 1/81 = x<BR>\n" );
document.write( "1/81 = 3^x<BR>\n" );
document.write( "1/(3^4) = 3^x<BR>\n" );
document.write( "since 81 = 3^4 and then<BR>\n" );
document.write( "3^(-4) = 3^x<BR>\n" );
document.write( "x = -4 </SPAN>\n" );
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