document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=46937>Question 46937</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find three consecutive odd integers such that three times the first minus the second is one more than the third. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #31088 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=31088\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find three consecutive odd integers such that three times the first minus the second is one more than the third.\r<BR>\n" );
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document.write( "1st odd number: 2x+1<BR>\n" );
document.write( "2nd odd number: 2x+3<BR>\n" );
document.write( "3rd odd number: 2x+5\r<BR>\n" );
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document.write( "EQUATION:<BR>\n" );
document.write( "3(2x+1)-(2x+3)-1=2x+5<BR>\n" );
document.write( "6x+3-2x-3-1=2x+5<BR>\n" );
document.write( "2x=6<BR>\n" );
document.write( "x=3<BR>\n" );
document.write( "2x+1=7 (1st odd)<BR>\n" );
document.write( "2x+3=9 (2nd odd)<BR>\n" );
document.write( "2x+5=11(3rd odd)<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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