document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=452217>Question 452217</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the area of to the nearest hundredth of a 10° sector in a circle with diameter 12 centimeters.\r<BR>\n" );
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document.write( "~thank you so much  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #310846 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=310846\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the area of (???) to the nearest hundredth of a 10° sector in a circle with diameter 12 centimeters.\r<BR>\n" );
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document.write( "Area of the circle = (pi)6^2 = 36pi<BR>\n" );
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document.write( "A 10 decree sector has 10/360 of the area<BR>\n" );
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document.write( "(10/360)(36pi) = (1/36)(36pi) = pi sq. cm.<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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