document.write( "Question 452193: The perimeter of a rectangle is 132 meters. The length is 9 meters more than twice the width. What are the dimensions. \n" ); document.write( "
Algebra.Com's Answer #310835 by Leaf W.(135)\"\" \"About 
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width: x
\n" ); document.write( "\"The length is 9 meters more than twice the width.\"
\n" ); document.write( "\"twice the width\": 2x
\n" ); document.write( "\"9 meters more than twice the width\": 2x + 9
\n" ); document.write( "Therefore, length: 2x + 9
\n" ); document.write( "The perimeter or a rectangle is denoted as 2(length) + 2(width). With the afore-said values of length and width, the perimeter is 2(2x + 9) + 2(x). Since the problem states that the perimeter is 132 meters:
\n" ); document.write( "2(2x + 9) + 2x = 132
\n" ); document.write( "Solve for x. Distribute the 2 into the 2x and 9:
\n" ); document.write( "4x + 18 + 2x = 132
\n" ); document.write( "Add like terms (4x and 2x):
\n" ); document.write( "6x + 18 = 132
\n" ); document.write( "Subtract 18 from both sides:
\n" ); document.write( "6x = 114
\n" ); document.write( "Divide both sides by 6:
\n" ); document.write( "x = 19
\n" ); document.write( "So, the width is 19 meters. To find the length, plug this value (19) in for x in the expression for length (2x + 9):
\n" ); document.write( "2x + 9
\n" ); document.write( "2(19) + 9
\n" ); document.write( "38 + 9
\n" ); document.write( "47
\n" ); document.write( "So, the length is 47 meters.
\n" ); document.write( "***Therefore, the length of the rectangle is 47 meters and the width of the rectangle is 19 meters. \n" ); document.write( "
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