document.write( "Question 46930This question is from textbook College Algebra
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document.write( ": Question #80: The altitude of an isosceles triangle drawn to its base is 3 centimeters, and its perimeter is 18 centimeters. Find the length of its base.
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document.write( " I wrote down the equation for the area of a triangle, but I don't recall from College Math how to find a triangle's perimeter. Area of a triangle: A=1/2(B)(H). I'm not sure how to solve this problem. Please help! \n" );
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Algebra.Com's Answer #31082 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! 2x+b=18 then b=18-2x or [(18-2x)/2]~2+3~2=x~2 or(9-x)~2+9=x~2 or\r \n" ); document.write( "\n" ); document.write( "81-16x+x~2+9=x~2 or 81-16x+9=0 or -16x+90=0 or 16x=90 or x=90/16 or x=5\r \n" ); document.write( "\n" ); document.write( "the 2*5+b=18 or b=18-10 or b=8 \n" ); document.write( " |