document.write( "Question 452054: Verify that the points (0,0),(a,0) and (a/2, square root symbol \"I don't know how to type it in\", with 3a/2 in it, are equilateral triangles. Then show that the midpoints of the three sides are the vertices of a second equilateral triangle. \n" ); document.write( "
Algebra.Com's Answer #310810 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "(0,0),(a,0) and (\"a%2F2\", \"sqrt%283a%2F2%29\" \r
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\n" ); document.write( "\n" ); document.write( "use Distance formula\r
\n" ); document.write( "\n" ); document.write( "(0,0) and (a,0)\r
\n" ); document.write( "\n" ); document.write( "\"D+=+sqrt%28%28a+-+0%29%5E2+%2B+%280+-+0%29%5E2%29\"\r
\n" ); document.write( "\n" ); document.write( "\"D+=+sqrt%28a%5E2%29\"\r
\n" ); document.write( "\n" ); document.write( "\"D+=+a\"\r
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\n" ); document.write( "\n" ); document.write( "(a,0) and ((a/2),(sqrt((3a)/2))\r
\n" ); document.write( "\n" ); document.write( "\"D+=+sqrt%28%28%28a%2F2%29+-+a%29%5E2+%2B+%28%28sqrt%283%29a%29%2F2%29+-+0%29%5E2%29\"\r
\n" ); document.write( "\n" ); document.write( "\"D+=+sqrt%28%28%28a%2F2%29+-+%282a%2F2%29%29%5E2+%2B+%28%28sqrt%283%29a%29%2F2%29%5E2%29\"\r
\n" ); document.write( "\n" ); document.write( "\"D+=+sqrt%28%28-a%2F2%29%5E2+%2B+%28%283a%5E2%29%2F4%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"D+=+sqrt%28%28%28a%5E2%29%2F4%29+%2B+%28%283a%5E2%29%2F4%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"D+=+sqrt%28%28a%5E2+%2B+3a%5E2%29%2F4%29\"\r
\n" ); document.write( "\n" ); document.write( "\"D+=+sqrt%28%284a%5E2%29%2F4%29\"\r
\n" ); document.write( "\n" ); document.write( "\"D+=+sqrt%28a%5E2%29\"\r
\n" ); document.write( "\n" ); document.write( "\"D+=+a\"\r
\n" ); document.write( "\n" ); document.write( "(0,0) and ((a/2), (sqrt(3)a/2))\r
\n" ); document.write( "\n" ); document.write( "\"D+=+sqrt%28%28%28a%2F2%29+-+0%29%5E2+%2B+%28%28sqrt%283%29a%2F2%29+-+0%29%5E2%29\"\r
\n" ); document.write( "\n" ); document.write( "\"D+=+sqrt%28%28a%2F2%29%5E2+%2B+%28%28sqrt%283%29a%29%2F2%29%5E2%29\"\r
\n" ); document.write( "\n" ); document.write( "\"D+=+sqrt%28%28%28a%5E2%29%2F4%29+%2B+%28%283a%5E2%29%2F4%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"D+=+sqrt%28%28a%5E2+%2B+3a%5E2%29%2F4%29\"\r
\n" ); document.write( "\n" ); document.write( "\"D+=+sqrt%284a%5E2%2F4%29\"\r
\n" ); document.write( "\n" ); document.write( "\"D+=+sqrt%28a%5E2%29\"\r
\n" ); document.write( "\n" ); document.write( "\"D+=+a\"\r
\n" ); document.write( "\n" ); document.write( "So, since they are \"all\"\"+equal\", this is an \"equilateral\" triangle.\r
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