document.write( "Question 451984: i am having troubles with solving the systems of equations in substitution. how do you solve the equation x-2y=0 and 4x-3y=15 in ordered pair form, (x,y)? \n" ); document.write( "

Algebra.Com's Answer #310734 by mananth(16946) $\"\"$ $\"About$

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x-2y=0 .............1
\n" ); document.write( "-3y=15-4x---------2
\n" ); document.write( "/-3 =
\n" ); document.write( "y=-5+1.33x
\n" ); document.write( "Plug the value of y in (1)
\n" ); document.write( "x-2(-5+ 1.33x)= 0
\n" ); document.write( "x+10-2.67x=0
\n" ); document.write( "x-2.67x =0-10
\n" ); document.write( "-1.67x=-10
\n" ); document.write( "/-1.67
\n" ); document.write( "x=6
\n" ); document.write( "Plug the value of x in (1)
\n" ); document.write( "x-2y=0
\n" ); document.write( "1*6-2y= 0
\n" ); document.write( "6-2y=0
\n" ); document.write( "-2y=-6
\n" ); document.write( "/-2
\n" ); document.write( "y=3
\n" ); document.write( "(2,3) \n" ); document.write( "

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