document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=451958>Question 451958</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Sam has a budget of $45 to spend on entertainment for the weekend. If he spent<BR>\n" );
document.write( "1/3 of his budget on Friday and 2/5 of his budget on Saturday, how many dollars does he have left over to spend on Sunday? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #310723 by </B><A HREF=/tutors/aboutme.mpl?userid=pedjajov><B>pedjajov(51)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=pedjajov><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=310723\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> $45 is spent on Friday (F), Saturday (S) and Sunday (N)\r<BR>\n" );
document.write( "\n" );
document.write( "F+S+N=45 -> N=45-F-S\r<BR>\n" );
document.write( "\n" );
document.write( "F is 1/3 of the budget so F=(1/3)*45 = $15<BR>\n" );
document.write( "S is 2/5 of the budget so S=(2/5)*45 = $18\r<BR>\n" );
document.write( "\n" );
document.write( "N=45-15-18 = $12 he can spend on Sunday. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );