document.write( "Question 451870: the perimeter of a rectangle is 36 cm. the area is 80 cm squared. find the length and width.\r
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\n" ); document.write( "\n" ); document.write( "i know the answers i just need how to get them. this is part of my area math packet. please help!
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Algebra.Com's Answer #310711 by jorel1380(3719)\"\" \"About 
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2L+2W=36
\n" ); document.write( "2L=36-2W
\n" ); document.write( "L=18-W
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\n" ); document.write( "W(18-W)=80
\n" ); document.write( "18W-W2=80
\n" ); document.write( "W2-18W+80=0
\n" ); document.write( "(W-10)(W-8)=0
\n" ); document.write( "W=8 or 10
\n" ); document.write( "Choosing the width to be 8 cm., we get the length to be 10 cm..
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