document.write( "Question 451934: In 1992, the FAA conducted 86,991 pre-employment drug tests on job applicants who were to be engaged in safety and security-related jobs, and found that 1,143 were positive. (a) Construct a 95 percent confidence interval for the population proportion of positive drug tests \n" ); document.write( "
Algebra.Com's Answer #310709 by stanbon(75887) ![]() You can put this solution on YOUR website! In 1992, the FAA conducted 86,991 pre-employment drug tests on job applicants who were to be engaged in safety and security-related jobs, and found that 1,143 were positive.\r \n" ); document.write( "\n" ); document.write( "----------------- \n" ); document.write( "p-hat = 1143/86991 = 0.013 \n" ); document.write( "--------------------- \n" ); document.write( " (a) Construct a 95 percent confidence interval for the population proportion of positive drug tests \n" ); document.write( "--- \n" ); document.write( "SE = 1.96*sqrt[0.013*0.987/86991] = 0.000753 \n" ); document.write( "=============== \n" ); document.write( "95% CI: 0.013-0.000753 < p < 0.013+0.000753 \n" ); document.write( "------ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |