document.write( "Question 451846: the perimeter of a rectangle is 14 feet and the area is 12 square ft what is the width \n" ); document.write( "
Algebra.Com's Answer #310698 by ankor@dixie-net.com(22740)\"\" \"About 
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the perimeter of a rectangle is 14 feet
\n" ); document.write( "2L + 2W = 14
\n" ); document.write( "Simplify, divide 2
\n" ); document.write( "L + W = 7
\n" ); document.write( "L = {7-W)
\n" ); document.write( ":
\n" ); document.write( "the area is 12 square ft what is the width
\n" ); document.write( "L*W = 12
\n" ); document.write( "replace L with (7-W), find W
\n" ); document.write( "W(7-W) = 12
\n" ); document.write( "-W^2 + 7W = 12
\n" ); document.write( "0 = W^2 - 7W + 12
\n" ); document.write( "Factors to
\n" ); document.write( "(W-4)(W-3) = 0
\n" ); document.write( "W = 4, then L = 3
\n" ); document.write( "or
\n" ); document.write( "W = 3, then L = 4 \n" ); document.write( "
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