document.write( "Question 451534: Debbie leaves the house walking at a rate of 3 miles per hour. After 10 minutes, her mother realizes that Debbie has forgotten her homework and leaves the house riding a bicycle at a rate of 10 miles per hour. How many minutes after Debbie initially left the house will her mother catch up to her? \n" ); document.write( "
Algebra.Com's Answer #310668 by ankor@dixie-net.com(22740)\"\" \"About 
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Debbie leaves the house walking at a rate of 3 miles per hour.
\n" ); document.write( " After 10 minutes, her mother realizes that Debbie has forgotten her homework and
\n" ); document.write( " leaves the house riding a bicycle at a rate of 10 miles per hour.
\n" ); document.write( " How many minutes after Debbie initially left the house will her mother catch up to her?
\n" ); document.write( ":
\n" ); document.write( "Convert 10 min to \"1%2F6\" hrs
\n" ); document.write( ":
\n" ); document.write( "Let t = D's travel time (hrs) when Mom catches her
\n" ); document.write( "then
\n" ); document.write( "(t - \"1%2F6\") = Mom's travel time
\n" ); document.write( ":
\n" ); document.write( "When Mom catches D, they will have traveled the same distance.
\n" ); document.write( "Write a distance equation; dist = speed*time
\n" ); document.write( "10(t-\"1%2F6\") = 3t
\n" ); document.write( "10t - \"10%2F6\" = 3t
\n" ); document.write( "10t - 3t = \"10%2F6\"
\n" ); document.write( "7t = \"10%2F6\"
\n" ); document.write( "multiply both sides by6
\n" ); document.write( "6*7t = 10
\n" ); document.write( "42t = 10
\n" ); document.write( "t = \"10%2F42\"
\n" ); document.write( "t = .2381 * 60 = 14.3 min is D's travel time, when Mom catches her.
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