document.write( "Question 451534: Debbie leaves the house walking at a rate of 3 miles per hour. After 10 minutes, her mother realizes that Debbie has forgotten her homework and leaves the house riding a bicycle at a rate of 10 miles per hour. How many minutes after Debbie initially left the house will her mother catch up to her? \n" ); document.write( "
Algebra.Com's Answer #310668 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Debbie leaves the house walking at a rate of 3 miles per hour. \n" ); document.write( " After 10 minutes, her mother realizes that Debbie has forgotten her homework and \n" ); document.write( " leaves the house riding a bicycle at a rate of 10 miles per hour. \n" ); document.write( " How many minutes after Debbie initially left the house will her mother catch up to her? \n" ); document.write( ": \n" ); document.write( "Convert 10 min to \n" ); document.write( ": \n" ); document.write( "Let t = D's travel time (hrs) when Mom catches her \n" ); document.write( "then \n" ); document.write( "(t - \n" ); document.write( ": \n" ); document.write( "When Mom catches D, they will have traveled the same distance. \n" ); document.write( "Write a distance equation; dist = speed*time \n" ); document.write( "10(t- \n" ); document.write( "10t - \n" ); document.write( "10t - 3t = \n" ); document.write( "7t = \n" ); document.write( "multiply both sides by6 \n" ); document.write( "6*7t = 10 \n" ); document.write( "42t = 10 \n" ); document.write( "t = \n" ); document.write( "t = .2381 * 60 = 14.3 min is D's travel time, when Mom catches her. \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( " |