document.write( "Question 451820: findall the real zeros of the function
\n" ); document.write( "f(x)=x^3-3x^2-x+3
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Algebra.Com's Answer #310652 by stanbon(75887)\"\" \"About 
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findall the real zeros of the function
\n" ); document.write( "f(x)=x^3-3x^2-x+3
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\n" ); document.write( "The sum of the coefficients is zero, so x = 1 is a root.
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\n" ); document.write( "1)....1....-3....-1....3
\n" ); document.write( ".......1.....-2....-3...|..0
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\n" ); document.write( "\n" ); document.write( "Quotient: x^2-2x-3
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\n" ); document.write( "Factor:
\n" ); document.write( "(x-3)(x+1) = 0
\n" ); document.write( "x = 3 or x = -1
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\n" ); document.write( "Final Answer:
\n" ); document.write( "x = 1, x = -1, x = 3
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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