document.write( "Question 451429: pls help.
\n" ); document.write( "write hyperbola 25y^2-4x^2+100y+24x-36=0 in
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\n" ); document.write( "\n" ); document.write( "also 25y^2-x^2=25
\n" ); document.write( "I put center (0,0) vertices (0,1) (0,-1)
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Algebra.Com's Answer #310546 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
 
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document.write( "Hi, 
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document.write( "Note: Standard Form of an Equation of an Hyperbola opening up and down is:
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document.write( "  \"%28y-k%29%5E2%2Fb%5E2+-+%28x-h%29%5E2%2Fa%5E2+=+1\" 
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document.write( "where Pt(h,k) is a center  with vertices 'b' units up and down from center.
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document.write( "25y^2-4x^2+100y+24x-36=0 
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document.write( " 25[(y+2)^2 -4] -4[(x-3)^2 - 9] - 36 = 0
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document.write( "   25(y+2)^2 -100 - 4(x-3)^2 + 36 - 36 = 0
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document.write( "   25(y+2)^2 - 4(x-3)^2 = 100
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document.write( "\"%28y%2B2%29%5E2%2F4+-%28x-3%29%5E2%2F25+=1\"  C(3,-2) with vertices V(3,0) and V(3,-4)
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document.write( "Foci: c = sqrt(29)  foci(-3, -2-sqrt(29)) and (-3, -2+sqrt(29))
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document.write( "25y^2-x^2=25
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document.write( " \"+y%5E2%2F1+-+x%5E2%2F25+=+1\" Yes. C(0,0) vertices(0,1),(0,-1)... foci(0,ħsqrt(26))  \n" );
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