document.write( "Question 451137: Solve:log(10^4x+3)=7 \n" ); document.write( "

Algebra.Com's Answer #310531 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( " log(10^4x+3)= (4x+3)log 10 = 7
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document.write( "  log 10 = 1  as 10^1 = 10
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document.write( "   4x+3 = 7
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document.write( "     4x = 4
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document.write( "      x = 1 \n" );
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