document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=451559>Question 451559</A>: <I><SPAN STYLE=\"word-break: break-all;\"> hi, i really hope you choose to help me with this as i'm completely stuck! how do you work out questions such as 3x+5(8-x)=24-x<BR>\n" );
document.write( "I have no idea where to start, and I also find problems like these with negative numbers extremely hard. Thank you for your time </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #310499 by </B><A HREF=/tutors/aboutme.mpl?userid=confusedgirl81><B>confusedgirl81(14)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=confusedgirl81><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=confusedgirl81><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=310499\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3x+5(8-x) = 24-x distribute 5 first<BR>\n" );
document.write( "3x+40-5x = 24-x <BR>\n" );
document.write( "-2x+40 = 24-x subtract 40 from both sides<BR>\n" );
document.write( "-2x = 24-40-x now add x to both sides<BR>\n" );
document.write( "-2x+x = 24-40 solve both sides, remember x is the same as 1x<BR>\n" );
document.write( "-1x = -16 divide both sides by -1<BR>\n" );
document.write( "x = 16\r<BR>\n" );
document.write( "\n" );
document.write( "when in doubt always check your answer<BR>\n" );
document.write( "3x+5(8-x) = 24-x now substitute 16 for x<BR>\n" );
document.write( "3(16)+5(8-16) = 24-16<BR>\n" );
document.write( "48+5(-8) = 8<BR>\n" );
document.write( "48-40 = 8<BR>\n" );
document.write( "8 = 8 \r<BR>\n" );
document.write( "\n" );
document.write( "so your answer is x = 16<BR>\n" );
document.write( " </SPAN>\n" );
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