document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=451555>Question 451555</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do i solve \"If f(2)=0 and f(x)=3x^2+kx-4,find k\" i need help solving this step by step. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #310494 by </B><A HREF=/tutors/aboutme.mpl?userid=tinbar><B>tinbar(133)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tinbar><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=310494\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> well, you know that f(2)=0, so let's find f(2) by actually plugging x=2 in the given function f(x)=3x^2+kx-4.<BR>\n" );
document.write( "f(2)=3(2^2)+k(2)-4=8+2k<BR>\n" );
document.write( "remember that f(2)=0, so we need to set 8+2k equal to 0 since they are both the same f(2)\r<BR>\n" );
document.write( "\n" );
document.write( "8+2k=0<BR>\n" );
document.write( "2k=-8<BR>\n" );
document.write( "k=-4 </SPAN>\n" );
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