document.write( "Question 451532: A plane travels 1200 miwith the wind in 2 hr. The return trip against the wind takes 3 hr. Find the rate of the plane. \n" ); document.write( "
Algebra.Com's Answer #310491 by pedjajov(51)\"\" \"About 
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Distance formula is r*t=d,\r
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\n" ); document.write( "\n" ); document.write( " - r = rate,
\n" ); document.write( " - t = time,
\n" ); document.write( " - d = distance.\r
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\n" ); document.write( "\n" ); document.write( "When travels with the wind that has its own rate w distance is \r
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\n" ); document.write( "\n" ); document.write( "(r+w)*t=d, wind \"pushes\" plane to move faster\r
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\n" ); document.write( "\n" ); document.write( "When travels against the wind distance is \r
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\n" ); document.write( "\n" ); document.write( "(r-w)*t=d, same distance but wind slows down the plane\r
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\n" ); document.write( "\n" ); document.write( "Now if we plug the values we have we get\r
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\n" ); document.write( "\n" ); document.write( "(r+w)*2=1200 -> r+w=600
\n" ); document.write( "(r-w)*3=1200 -> r-w=400\r
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\n" ); document.write( "\n" ); document.write( "If we add these two equations we get:\r
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\n" ); document.write( "\n" ); document.write( "2r=1000
\n" ); document.write( " r=500mi/h is a rate of the plane.\r
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\n" ); document.write( "\n" ); document.write( " w=600-r
\n" ); document.write( " w=100mi/h is a rate of the wind.
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