document.write( "Question 451550: Noah can row 30 km downstream in 1.5 hr.Rowing upstream against the current he travels 12 km in 1.5 hr. Find the rate Noah rows and the rate of the current. \n" ); document.write( "
Algebra.Com's Answer #310488 by pedjajov(51)\"\" \"About 
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Formula for distance is r*t=d where\r
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\n" ); document.write( "\n" ); document.write( "- r is a rate (speed) of movement of the object
\n" ); document.write( "- t is a time measured during the movement of the object
\n" ); document.write( "- d is a distance traveled during the movement of the object\r
\n" ); document.write( "\n" ); document.write( "We have to take in the rate of the river current - c.\r
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\n" ); document.write( "\n" ); document.write( "So for the downstream we have:\r
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\n" ); document.write( "\n" ); document.write( "(r+c)*t=d\r
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\n" ); document.write( "\n" ); document.write( "Going upstream Noah travels against the current of the river, which rate we can mark as c) so the distance becomes \r
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\n" ); document.write( "\n" ); document.write( "(r-c)*t=d, river slows down Noah\r
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\n" ); document.write( "\n" ); document.write( "If we plug all the values we know we get\r
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\n" ); document.write( "\n" ); document.write( "(r+c)*1.5=30
\n" ); document.write( "(r-c)*1.5=12\r
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\n" ); document.write( "\n" ); document.write( "Dividing both equations by 1.5 we get\r
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\n" ); document.write( "\n" ); document.write( "r+c=20
\n" ); document.write( "r-c=8\r
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\n" ); document.write( "\n" ); document.write( "If we add these two equations we get\r
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\n" ); document.write( "\n" ); document.write( "2r=28
\n" ); document.write( "r =14km/h, rate for Noah\r
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\n" ); document.write( "\n" ); document.write( "Go back to find rate of the current:\r
\n" ); document.write( "\n" ); document.write( "r+c=20
\n" ); document.write( "c =20-r
\n" ); document.write( "c =20-14
\n" ); document.write( "c =6km/h\r
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\n" ); document.write( "\n" ); document.write( "Rate for the river current is 6km/h.
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