document.write( "Question 451510: Answer this quesion four brother were born in two year intervals, the sum of their ages is 36. Find the age of each. \n" ); document.write( "

Algebra.Com's Answer #310466 by pedjajov(51) $\"\"$ $\"About$

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Let's mark the age of each brother with B1, B2, B3, B4\r
\n" ); document.write( "\n" ); document.write( "B1 = x - youngest brother's age is x years
\n" ); document.write( "B2 = x + 2 - next brother is 2 years older then the youngest
\n" ); document.write( "B3 = x + 4 - next brother is 2 years older than the previous brother
\n" ); document.write( "B4 = x + 6 - next brother is 2 years older than the previous brother\r
\n" ); document.write( "\n" ); document.write( "Sum of all their ages is 36:\r
\n" ); document.write( "\n" ); document.write( "B1 + B2 + B3 + B4 = 36\r
\n" ); document.write( "\n" ); document.write( "x + (x + 2) + (x + 4) + (x + 6) = 36
\n" ); document.write( "x + x + 2 + x + 4 + x +6 = 36
\n" ); document.write( "4x + 12 = 36
\n" ); document.write( "4x = 36 -12 = 24
\n" ); document.write( "x = 24/4
\n" ); document.write( "x = 6\r
\n" ); document.write( "\n" ); document.write( "Now when we know the age of the youngest brother we can find ages of all 4:\r
\n" ); document.write( "\n" ); document.write( "B1 = 6
\n" ); document.write( "B2 = 8
\n" ); document.write( "B3 = 10
\n" ); document.write( "B4 = 12\r
\n" ); document.write( "\n" ); document.write( "Check: 6 + 8 + 10 + 12 = 36 \n" ); document.write( "

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