document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=451435>Question 451435</A>: <I><SPAN STYLE=\"word-break: break-all;\"> pure acid is to be added to a 20% solution to obtain 60 liters of a 30% acid solution. what amounts of each should be used? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #310460 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=310460\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1.00x + 0.20(60-x) = 0.30*60\r<BR>\n" );
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document.write( "==> x + 12 - 0.20x = 18\r<BR>\n" );
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document.write( "==> 0.80x = 6\r<BR>\n" );
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document.write( "==> x = 7.5 liters of pure acid, and <BR>\n" );
document.write( "60 - x = 52.5 liters of the 20% acid. </SPAN>\n" );
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