document.write( "Question 1352: how do u solve 3x +15 when x=12
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Algebra.Com's Answer #310417 by solver15(27)![]() ![]() You can put this solution on YOUR website! 3x +15 when x=12\r \n" ); document.write( "\n" ); document.write( "plug in the 12 to x \n" ); document.write( "3(12)+15 \n" ); document.write( "36+15 \n" ); document.write( "=51 \n" ); document.write( " |