document.write( "Question 451383: Trying to help my little brother with his homework, with little success.\r
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document.write( "Pipes A and B take 8 hours to fill a pool. Pipe A is twice the size of pipe B. How long would it take to fill the pool using only pipe A?\r
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document.write( "We believe 2 + 2b = 8 would be a logical starting place, but don't know where to go from there.\r
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document.write( "Thanks for any help. \n" );
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Algebra.Com's Answer #310400 by jorel1380(3719) You can put this solution on YOUR website! If pipe A is twice as big as pipe B, then it is safe to assume that pipe B takes twice as long as pipe A to fill the pool. Therefore: \n" ); document.write( "Pipe A + Pipe B=1/8 pool per hour \n" ); document.write( "1/t+1/2t=1/8 \n" ); document.write( "8+4=t \n" ); document.write( "t=12 \n" ); document.write( "Pipe A takes 12 hours to fill the pool alone; pipe B takes 24 hours to fill the pool alone.. \n" ); document.write( " |