document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=451381>Question 451381</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what is the volume of the empty space left when three tennis balls with a diameter of 3 inches are packed into a cylindrical container that is 9 inches tall with the same diameter as the tennis ball? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #310398 by </B><A HREF=/tutors/aboutme.mpl?userid=kingme18><B>kingme18(98)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=kingme18><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=kingme18><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=310398\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> To find the volume of the leftover space, you need to find the total volume (volume of the cylinder) and the volume of the balls (spheres), then subtract to find everything IN the cylinder and OUTSIDE the balls.  Note that for both the cylinder and the spheres, the radius is 1.5 since the diameter is 3.<BR>\n" );
document.write( "The formula for the volume of a cylinder is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+pi%2Ar%5E2%2Ah+ ALIGN=MIDDLE  ALT=\"+pi%2Ar%5E2%2Ah+\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  This is approximately <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+3.14%2A1.5%5E2%2A9=63.585 ALIGN=MIDDLE  ALT=\"+3.14%2A1.5%5E2%2A9=63.585\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  The volume of a sphere is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+4%2F3%2Api%2Ar%5E3 ALIGN=MIDDLE  ALT=\"+4%2F3%2Api%2Ar%5E3\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  In your case, this is about <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4%2F3%2A3.14%2A1.5%5E3=14.13 ALIGN=MIDDLE  ALT=\"4%2F3%2A3.14%2A1.5%5E3=14.13\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  However, there are 3 balls.  Since each one is 14.13 cubic inches, we'll multiply by 3 and get 42.39.  We can now subtract the total minus the balls: 63.585-42.39=21.195 cubic inches. </SPAN>\n" );
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