document.write( "Question 451377: I'm so lost\r
\n" ); document.write( "\n" ); document.write( "The function h is is defined below
\n" ); document.write( "h(x)=(x+6)/(x^2+9x+8) \r
\n" ); document.write( "\n" ); document.write( "Find all values of x that are NOT in the domain of h. \r
\n" ); document.write( "\n" ); document.write( "If there is more than one value, separate them with commas. \n" ); document.write( "
Algebra.Com's Answer #310390 by kingme18(98)\"\" \"About 
You can put this solution on YOUR website!
The domain of a function is everything that x can't ever equal. In some cases, there are numerous places (for example, for the square root function x can't be negative). For a function like yours, the only problems will be when the denominator equals zero. This is because you're not allowed to divide by 0.\r
\n" ); document.write( "\n" ); document.write( "So, let's look at the denominator. Any x value that would make it equal zero is illegal, so it's NOT in the domain. \"+x%5E2%2B9x%2B8=0+\" Let's factor! \"+%28x%2B8%29%28x%2B1%29=0+\" Since two things multiply to 0, one of them must actually be equal to 0. So \"+x%2B8=0+\" or \"+x%2B1=0+\". When you solve those, you get that x=-8 and x=-1. Those are the two values that x CANNOT equal; therefore, they aren't in the domain. \n" ); document.write( "
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