document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=451291>Question 451291</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am a 3-digit number less than 300. I am divisible by 2 and 5, but not 3. The sum of my digits is 7. What number am I? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #310351 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=310351\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Since the number is \"divisible by 2 and 5\", this means that the number is divisible by 10 (since 2*5 = 10). So the number ends with a 0. \r<BR>\n" );
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document.write( "So the possible numbers are: \r<BR>\n" );
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document.write( "100, 110, 120, 130, 140, 150, 160, 170, 180, 190, <BR>\n" );
document.write( "200, 210, 220, 230, 240, 250, 260, 270, 280, 290\r<BR>\n" );
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document.write( "Now add up the digits of each possible number. The digits that add to 7 will give us the number. It turns out that 160 and 250 fit this description since 1+6+0=7 and 2+5+0=7\r<BR>\n" );
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document.write( "So the numbers are 160 and 250. </SPAN>\n" );
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