document.write( "Question 451262: How would one go about answering an equation like: x * log(3) - x = ln(7) ? \n" ); document.write( "
Algebra.Com's Answer #310345 by Alan3354(69443)\"\" \"About 
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How would one go about answering an equation like: x * log(3) - x = ln(7) ?
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\n" ); document.write( "log(3) and ln(7) are constants.
\n" ); document.write( "x * log(3) - x = ln(7)
\n" ); document.write( "x*(log(3) - 1) = ln(7)
\n" ); document.write( "x = ln(7)/(log(3) - 1)
\n" ); document.write( "x =~ -3.72153
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