document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=451138>Question 451138</A>: <I><SPAN STYLE=\"word-break: break-all;\"> one canned juice drink is 30% orange juice; another is 5% orange juice. how many liters of each should be mixed together in order to get 25L THAT IS 25% ORANGE JUICE? HOW MANY LITERS OF 30% ORANGE JUICE SHOULD BE IN THE MIXTURE? How many liters of 5% orange juice should be in the mixture? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #310332 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=310332\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 25 lrs. of 25% o.j.=6.25 lrs. pure o.j.<BR>\n" );
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document.write( "m+n=25<BR>\n" );
document.write( ".3m+.05n=6.25<BR>\n" );
document.write( "30m+5n=625<BR>\n" );
document.write( "5m+5n=125<BR>\n" );
document.write( "25m=500<BR>\n" );
document.write( "m=20<BR>\n" );
document.write( "n=5<BR>\n" );
document.write( "You need 20 lrs. of 30% o.j. and 5 lrs. of 5% o.j. for the desired mix..<BR>\n" );
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