document.write( "Question 451238: Twenty liters of a 20% acid solution is obtained by mixing 30% acid solution and a 5% acid solution. How many liters of each solution are needed to obtain the specified mixture? \n" ); document.write( "
Algebra.Com's Answer #310324 by jorel1380(3719)![]() ![]() You can put this solution on YOUR website! 20ltr.x.20=4 ltrs. pure acid \n" ); document.write( "----------------- \n" ); document.write( "m+n=20 \n" ); document.write( ".30m+.05n=4 \n" ); document.write( "30m+5n=400 \n" ); document.write( "5m+5n=100 \n" ); document.write( "25m=300 \n" ); document.write( "m=12 \n" ); document.write( "You need 12 ltrs. of 30% solution to 8 ltrs. of 5% solution.. \n" ); document.write( " |