document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=451215>Question 451215</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is twice the width.     If the length is increased by 4 inches and the width is diminished by 1 inch, a new rectangle is formed whose perimeter is 198 inches.     Fine the dimensions of the original rectangle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #310313 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=310313\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is twice the width. If the length is increased by 4 inches and the width is diminished by 1 inch, a new rectangle is formed whose perimeter is 198 inches. Fine the dimensions of the original rectangle<BR>\n" );
document.write( "..<BR>\n" );
document.write( "let x=original length=2y<BR>\n" );
document.write( "let y=original width<BR>\n" );
document.write( "length increased by 4=x+4<BR>\n" );
document.write( "width deminished by 1=y-1<BR>\n" );
document.write( "Perimeter=2*length+2*width=198<BR>\n" );
document.write( "2(x+4)+2(y-1)=198<BR>\n" );
document.write( "2x+8+2y-2=198<BR>\n" );
document.write( "substitute x for 2y<BR>\n" );
document.write( "2x+8+x-2=198<BR>\n" );
document.write( "3x=192<BR>\n" );
document.write( "x=64 inches<BR>\n" );
document.write( "y=x/2=64/2=32 inches<BR>\n" );
document.write( "Ans:<BR>\n" );
document.write( "Dimensions of original triangle: 64 by 32 inches </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );