document.write( "Question 451013: graph the parabolas\r
\n" ); document.write( "\n" ); document.write( "y = 1/2(x-1)^2\r
\n" ); document.write( "\n" ); document.write( "x=-1/4(y+1)^2 +2
\n" ); document.write( "

Algebra.Com's Answer #310208 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
graph the parabolas
\n" ); document.write( "y = 1/2(x-1)^2
\n" ); document.write( "x=-1/4(y+1)^2 +2
\n" ); document.write( "..
\n" ); document.write( "y = 1/2(x-1)^2
\n" ); document.write( "This equation is a parabola of the form, y=A(x-h)^2+k.
\n" ); document.write( "For given equation, y = 1/2(x-1)^2
\n" ); document.write( "Curve opens upwards
\n" ); document.write( "(x,y) coordinates of the vertex= (h,k)=(1,0)
\n" ); document.write( "Axis of symmetry x=1
\n" ); document.write( "A=1/2 (The larger the narrower the curve)
\n" ); document.write( "With this information and one other point on the curve, you should be able to graph this parabola.
\n" ); document.write( "Your graph should look much like the one below.
\n" ); document.write( "..
\n" ); document.write( "\"+graph%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2C+.5%28x-1%29%5E2%29+\"
\n" ); document.write( "..
\n" ); document.write( "x=-1/4(y+1)^2 +2
\n" ); document.write( "This equation is a parabola of the form, x=-A(y-k)^2+h.
\n" ); document.write( "For given equation, x=-1/4(y+1)^2 +2
\n" ); document.write( "Curve opens leftwards
\n" ); document.write( "(x,y) coordinates of the vertex= (h,k)=(2,-1)
\n" ); document.write( "Axis of symmetry y=-1
\n" ); document.write( "A=-1/4 (The larger the narrower the curve)
\n" ); document.write( "With this information and one other point on the curve, you should be able to graph this parabola.
\n" ); document.write( "Your graph should look much like the one below.
\n" ); document.write( "..
\n" ); document.write( "y=(-4x+8)^.5-1\r
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