document.write( "Question 451013: graph the parabolas\r
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document.write( "y = 1/2(x-1)^2\r
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document.write( "x=-1/4(y+1)^2 +2 \n" );
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Algebra.Com's Answer #310208 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! graph the parabolas \n" ); document.write( "y = 1/2(x-1)^2 \n" ); document.write( "x=-1/4(y+1)^2 +2 \n" ); document.write( ".. \n" ); document.write( "y = 1/2(x-1)^2 \n" ); document.write( "This equation is a parabola of the form, y=A(x-h)^2+k. \n" ); document.write( "For given equation, y = 1/2(x-1)^2 \n" ); document.write( "Curve opens upwards \n" ); document.write( "(x,y) coordinates of the vertex= (h,k)=(1,0) \n" ); document.write( "Axis of symmetry x=1 \n" ); document.write( "A=1/2 (The larger the narrower the curve) \n" ); document.write( "With this information and one other point on the curve, you should be able to graph this parabola. \n" ); document.write( "Your graph should look much like the one below. \n" ); document.write( ".. \n" ); document.write( " \n" ); document.write( ".. \n" ); document.write( "x=-1/4(y+1)^2 +2 \n" ); document.write( "This equation is a parabola of the form, x=-A(y-k)^2+h. \n" ); document.write( "For given equation, x=-1/4(y+1)^2 +2 \n" ); document.write( "Curve opens leftwards \n" ); document.write( "(x,y) coordinates of the vertex= (h,k)=(2,-1) \n" ); document.write( "Axis of symmetry y=-1 \n" ); document.write( "A=-1/4 (The larger the narrower the curve) \n" ); document.write( "With this information and one other point on the curve, you should be able to graph this parabola. \n" ); document.write( "Your graph should look much like the one below. \n" ); document.write( ".. \n" ); document.write( "y=(-4x+8)^.5-1\r \n" ); document.write( "\n" ); document.write( " |