document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=451056>Question 451056</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this problem:<BR>\n" );
document.write( "Find the solutions on the interval [0,2pi).<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #310168 by </B><A HREF=/tutors/aboutme.mpl?userid=tinbar><B>tinbar(133)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tinbar><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=310168\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> factor out the cos(x)<BR>\n" );
document.write( "you get cos(x)[sqrt(2)sin(x)-1)]=0\r<BR>\n" );
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document.write( "from this it follows that either cos(x)= 0 or [sqrt(2)sin(x)-1)] = 0\r<BR>\n" );
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document.write( "if cos(x)=0, then in the given interval, you should get two solutions, i'll leave it to you to find them.\r<BR>\n" );
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document.write( "if [sqrt(2)sin(x)-1)] = 0 then x = sinInverse(1/sqrt(2)), and once again you'll get two solutions </SPAN>\n" );
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