document.write( "Question 451035: a long-distance runner left his house running at an average rate of 8 miles per hour. fifteen minutes (one-fourth of an hour) later, his son left his house on his bike traveling on the same route at an average rate of 12 miles per hour. how long will it take the son to catch up with his father? \n" ); document.write( "
Algebra.Com's Answer #310160 by edjones(8007)\"\" \"About 
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speed * time = distance
\n" ); document.write( "Let t=son's time
\n" ); document.write( "8(t+.25)=father's dist.
\n" ); document.write( "12t=son's dist.
\n" ); document.write( "12t=8t+2 distances are equal when the son catches up.
\n" ); document.write( "4t=2
\n" ); document.write( "t= 1/2 hour.
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