document.write( "Question 450920: A committee is to consist of three members. If there are seven men and five women available to serve on the committee, how many different committees can be formed?\r
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document.write( "I've tried listing all the possible combinations for committee memberships but I'm already up to 13+ committees and I'm certain there must be an easier way. Please help! \n" );
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Algebra.Com's Answer #310092 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A committee is to consist of three members. \n" ); document.write( "If there are seven men and five women available to serve on the committee, how many different committees can be formed? \n" ); document.write( "----- \n" ); document.write( "0 men: 5C3 = 10 committees \n" ); document.write( "--- \n" ); document.write( "1 man: 7C1*5C2 = 7*10 = 70 committees \n" ); document.write( "--- \n" ); document.write( "2 men: 7C2*5C1 = 21*5 = 105 committees \n" ); document.write( "--- \n" ); document.write( "3 men: 7C3 = 35 committees \n" ); document.write( "----------------------------------------- \n" ); document.write( "Total # of committees: 10+70+105+35 = 220 \n" ); document.write( "=================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |