document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=450801>Question 450801</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2x+(3/4)(4x+16)=7<BR>\n" );
document.write( "(3/4) is a fraction just so you know </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #310039 by </B><A HREF=/tutors/aboutme.mpl?userid=natnat1224><B>natnat1224(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=natnat1224><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=310039\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2x+(3/4)(4x+16)=7<BR>\n" );
document.write( "First, you distribute the 3/4 to the 4x and the 16.<BR>\n" );
document.write( "2x+(3/4)(4x)+(3/4)(16)=7<BR>\n" );
document.write( "2x+3+12=7<BR>\n" );
document.write( "Then you add the 3 and the 12.<BR>\n" );
document.write( "2x+15=7<BR>\n" );
document.write( "Then you move the 15 from the left to the right (subtract it from the 7.<BR>\n" );
document.write( "2x=7-15<BR>\n" );
document.write( "2x=-8<BR>\n" );
document.write( "Finally you divide the 2 to both sides.<BR>\n" );
document.write( "x=-8/2<BR>\n" );
document.write( "x=-4<BR>\n" );
document.write( "The final answer is -4.  </SPAN>\n" );
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