document.write( "Question 450807: Thanks for answering! WILL LEAVE GREAT COMMENT FOR YOU !\r
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document.write( "Two years from now, Jim will be twice as old as Joe will then be. Ten years ago, Jim was 5 times as old as Joe was. Find the present age of each person.\r
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document.write( "GOD BLESS! \n" );
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Algebra.Com's Answer #310032 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Let x = Jim's present age \n" ); document.write( "Let y = Joe's present age \n" ); document.write( ": \n" ); document.write( "\"Two years from now, Jim will be twice as old as Joe will then be.\" \n" ); document.write( "x + 2 = 2(y+2) \n" ); document.write( "x + 2 = 2y + 4 \n" ); document.write( "x = 2y + 4 - 2 \n" ); document.write( "x = 2y + 2 \n" ); document.write( ": \n" ); document.write( "\"Ten years ago, Jim was 5 times as old as Joe was.\" \n" ); document.write( "x - 10 = 5(y - 10) \n" ); document.write( "x - 10 = 5y - 50 \n" ); document.write( "x = 5y - 50 + 10 \n" ); document.write( "x = 5y - 40 \n" ); document.write( ": \n" ); document.write( "Replace x in the 1st equation with (5y-40) \n" ); document.write( "5y - 40 = 2y + 2 \n" ); document.write( "5y - 2y = 2 + 40 \n" ); document.write( "3y = 42 \n" ); document.write( "y = \n" ); document.write( "y = 14 yr Joe's present age \n" ); document.write( ": \n" ); document.write( "then \n" ); document.write( "x = 2(14) + 2 \n" ); document.write( "x = 30 yrs is Jim's age \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solutions in the statement: \n" ); document.write( "\"Ten years ago, Jim was 5 times as old as Joe was.\" \n" ); document.write( "30 - 10 = 5(14 - 10) \n" ); document.write( "20 = 5(4); confirms our solutions \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Looking forward to that comment!\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |