document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=450713>Question 450713</A>: <I><SPAN STYLE=\"word-break: break-all;\"> rewrite as a logarithmic equation<BR>\n" );
document.write( "2^-4= 1/16 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #310026 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=310026\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> rewrite as a logarithmic equation<BR>\n" );
document.write( "2^-4= 1/16<BR>\n" );
document.write( "..<BR>\n" );
document.write( "What you have here is the exponential form of a logarithm which is defined as:<BR>\n" );
document.write( "The base(2) raised to the logarithm of the number(-4) is = number(1/16)<BR>\n" );
document.write( "..<BR>\n" );
document.write( "To write it in logarithmic form, then: log2(1/16)=-4. In words this form says: the logarithm of 1/16 to the base 2 is equal to -4. </SPAN>\n" );
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