document.write( "Question 450562: what is the answer and the steps to this equation?
\n" );
document.write( "(log(x-1)^2)^4+(log(x-1)^3)^2=25 \n" );
document.write( "
Algebra.Com's Answer #310024 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! what is the answer and the steps to this equation? \n" ); document.write( "(log(x-1)^2)^4+(log(x-1)^3)^2=25 \n" ); document.write( ".. \n" ); document.write( "(log(x-1)^2)^4+(log(x-1)^3)^2=25 \n" ); document.write( "(2log(x-1))^4+(3log(x-1))^2=25 \n" ); document.write( "16(log(x-1))^4+9(log(x-1))^2=25 \n" ); document.write( "let u=(log(x-1))^2 \n" ); document.write( "then u^2=log(x-1)^4 \n" ); document.write( "16u^2+9u=25 \n" ); document.write( "16u^2+9u_25=0 \n" ); document.write( "Solve by quadratic formula below: \n" ); document.write( ".. \n" ); document.write( " \n" ); document.write( ".. \n" ); document.write( "a=16, b=9, c=-25 \n" ); document.write( "u=[-9ħsqrt(9^2-4*16*-25)]/2*16 \n" ); document.write( "u=[-9ħsqrt(1681)]/32 \n" ); document.write( "u=(-9ħ41)/32 \n" ); document.write( "u=(-9+41)/32=32/32=1 \n" ); document.write( "or \n" ); document.write( "u=(-9-41)/32=-50/32=-1.56250 (reject) \n" ); document.write( ".. \n" ); document.write( "u=(log(x-1))^2=1 \n" ); document.write( "take sqrt of both sides \n" ); document.write( "log(x-1)=1 \n" ); document.write( "convert to exponential form \n" ); document.write( "10^1=x-1=10 \n" ); document.write( "x=11\r \n" ); document.write( "\n" ); document.write( "Check: \n" ); document.write( "(log(x-1)^2)^4+(log(x-1)^3)^2 \n" ); document.write( "(2log(x-1))^4+(3log(x-1))^ \n" ); document.write( "(2log(11-1))^4+(3log(11-1)^2 \n" ); document.write( "2log(10)^4+3log(10)^2 \n" ); document.write( "log(10)=1 \n" ); document.write( "2^4+3^2=16+9=25 \n" ); document.write( ".. \n" ); document.write( " |