document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=450602>Question 450602</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a picture frame is 2 inches greater than its width. If the area of the frame is 143 sq inches, what is its width?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #309920 by </B><A HREF=/tutors/aboutme.mpl?userid=rwm><B>rwm(914)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rwm><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=309920\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L=W+2<BR>\n" );
document.write( "area =length times width<BR>\n" );
document.write( "A=L*W<BR>\n" );
document.write( "A=(W+2)*W<BR>\n" );
document.write( "143=(W+2)*W\r<BR>\n" );
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document.write( "143=W^2+2W<BR>\n" );
document.write( "W^2+2W-143=0<BR>\n" );
document.write( "find factors of -143 which add up to 2<BR>\n" );
document.write( "-11 and 13 fit\r<BR>\n" );
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document.write( "(W-11)*(W+13)=0<BR>\n" );
document.write( "W=11<BR>\n" );
document.write( "W=-13<BR>\n" );
document.write( "We can't use negative measurements.<BR>\n" );
document.write( "11 and 11+2<BR>\n" );
document.write( "11 and 13<BR>\n" );
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