document.write( "Question 450304: What is the length of the transverse axis of the hyperbola defined by the equation below? (y-6)^2/6^2-(x+5)^2/12^2=1 \n" ); document.write( "
Algebra.Com's Answer #309852 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! What is the length of the transverse axis of the hyperbola defined by the equation below\r \n" ); document.write( "\n" ); document.write( " (y-6)^2/6^2-(x+5)^2/12^2=1 \n" ); document.write( ".. \n" ); document.write( "Standard form of hyperbola with horizontal transverse axis: (x-h)^2/a^2-(y-k)^2/b^2=1, \n" ); document.write( "with (h,k) being the (x,y) coordinates of the center. \n" ); document.write( "Standard form of hyperbola with vertical transverse axis: (y-k)^2/a^2-(x-h)^2/b^2=1, with (h,k) being the (x,y) coordinates of the center. \n" ); document.write( "The difference between these two forms is that the (x-h)^2 and (y-k)^2 terms are interchanged. \n" ); document.write( ".. \n" ); document.write( "Given equation of hyperbola: (y-6)^2/6^2-(x+5)^2/12^2=1 \n" ); document.write( "This is a hyperbola of the 2nd form listed. It has a vertical transverse axis with center at (-5,6). \n" ); document.write( "a^2=6^2 \n" ); document.write( "a=6=distance from center to vertex \n" ); document.write( "Length of transverse axis=distance between vertices=2a=12 \n" ); document.write( "See the graph below for visual evidence of the algebra above:\r \n" ); document.write( "\n" ); document.write( ".. \n" ); document.write( "y=(36(1+(x+5)^2/144))^.5+6 \n" ); document.write( " |