document.write( "Question 450278: how do u graph (x-3)^2 divided by 25 + (y+6)^2 divided by 49 = 1 \n" ); document.write( "
Algebra.Com's Answer #309851 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! how do u graph (x-3)^2 divided by 25 + (y+6)^2 divided by 49 = 1 \n" ); document.write( ".. \n" ); document.write( "Standard form for ellipse with horizontal major axis: (x-h)^2/a^2+(y-k)^2/b^2=1 (a>b), with (h,k) being the (x,y) coordinates of the center \n" ); document.write( "Standard form for ellipse with vertical major axis: (x-h)^2/b^2+(y-k)^2/a^2=1 (a>b),with (h,k) being the (x,y) coordinates of the center \n" ); document.write( "The only difference between the two forms is that a^2 and b^2 are interchanged \n" ); document.write( ".. \n" ); document.write( "Given equation in standard form: (x-3)^2/25+(y+6)^2/49=1 \n" ); document.write( "This is an ellipse with center at (3,-6). It has a vertical major axis because the larger denominator is under the y-term. (2nd form listed above) \n" ); document.write( "Other information needed for graphing: \n" ); document.write( "a^2=49 \n" ); document.write( "a=7 \n" ); document.write( "length of major axis =2a=14 \n" ); document.write( "b^2=25 \n" ); document.write( "b=5 \n" ); document.write( "length of minor axis =2b=10 \n" ); document.write( "c^2=a^2-b^2=49-25=24 \n" ); document.write( "c=√24=4.9 \n" ); document.write( "End points of major axis or location of vertices: (3,-6±7) \n" ); document.write( "Location of foci: (3,-6±√24) \n" ); document.write( "You now have the information you need to graph equation of given ellipse.\r \n" ); document.write( "\n" ); document.write( "Your graph should look much like the graph below:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( ".. \n" ); document.write( "y=(49(1-(x-3)^2/25))^.5-6\r \n" ); document.write( "\n" ); document.write( " |