document.write( "Question 450278: how do u graph (x-3)^2 divided by 25 + (y+6)^2 divided by 49 = 1 \n" ); document.write( "
Algebra.Com's Answer #309851 by lwsshak3(11628)\"\" \"About 
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how do u graph (x-3)^2 divided by 25 + (y+6)^2 divided by 49 = 1
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\n" ); document.write( "Standard form for ellipse with horizontal major axis: (x-h)^2/a^2+(y-k)^2/b^2=1 (a>b), with (h,k) being the (x,y) coordinates of the center
\n" ); document.write( "Standard form for ellipse with vertical major axis: (x-h)^2/b^2+(y-k)^2/a^2=1 (a>b),with (h,k) being the (x,y) coordinates of the center
\n" ); document.write( "The only difference between the two forms is that a^2 and b^2 are interchanged
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\n" ); document.write( "Given equation in standard form: (x-3)^2/25+(y+6)^2/49=1
\n" ); document.write( "This is an ellipse with center at (3,-6). It has a vertical major axis because the larger denominator is under the y-term. (2nd form listed above)
\n" ); document.write( "Other information needed for graphing:
\n" ); document.write( "a^2=49
\n" ); document.write( "a=7
\n" ); document.write( "length of major axis =2a=14
\n" ); document.write( "b^2=25
\n" ); document.write( "b=5
\n" ); document.write( "length of minor axis =2b=10
\n" ); document.write( "c^2=a^2-b^2=49-25=24
\n" ); document.write( "c=√24=4.9
\n" ); document.write( "End points of major axis or location of vertices: (3,-6±7)
\n" ); document.write( "Location of foci: (3,-6±√24)
\n" ); document.write( "You now have the information you need to graph equation of given ellipse.\r
\n" ); document.write( "\n" ); document.write( "Your graph should look much like the graph below:\r
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\n" ); document.write( "\n" ); document.write( "..
\n" ); document.write( "y=(49(1-(x-3)^2/25))^.5-6\r
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