document.write( "Question 450452: The length of a rectangle is 7 inches more than three times the width. The perimeter is 94 inches. Find the length and width \n" ); document.write( "
Algebra.Com's Answer #309822 by algebrahouse.com(1659)![]() ![]() You can put this solution on YOUR website! \"The length of a rectangle is 7 inches more than three times the width. The perimeter is 94 inches. Find the length and width\"\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = width \n" ); document.write( "3x + 7 = length {length is 7 more than 3 times width}\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Perimeter of a rectangle = 2(width) + 2(length)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2x + 2(3x + 7) = 94 {perimeter is 2 x width + 2 x length} \n" ); document.write( "2x + 6x + 14 = 94 {used distributive property} \n" ); document.write( "8x + 14 = 94 {combined like terms} \n" ); document.write( "8x = 80 {subtracted 14 from both sides} \n" ); document.write( "x = 10 {divided both sides by 8} \n" ); document.write( "3x + 7 = 37 {substituted 10, in for x, into 3x + 7}\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "width = 10 in. \n" ); document.write( "length = 37 in. \n" ); document.write( "www.algebrahouse.com \n" ); document.write( " |