document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=450429>Question 450429</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An alloy of tin is 15% tin and weighs 20 pounds. A second alloy is 10% tin. How many pounds of the second alloy must be added to the first to get a 12% mixture?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #309806 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=309806\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> ------	percent	----------------	quantity										<BR>\n" );
document.write( "Alloy I	15	----------------20	pounds							<BR>\n" );
document.write( "Alloy II	10	----------------x pounds							<BR>\n" );
document.write( "Total	12----------------20+x	pounds							<BR>\n" );
document.write( "													<BR>\n" );
document.write( "15*20+10*x=12(20+x)							<BR>\n" );
document.write( "300+10x=240+12x					<BR>\n" );
document.write( "10x-12x=240-300					<BR>\n" );
document.write( "-2x=-60										<BR>\n" );
document.write( "/-2										<BR>\n" );
document.write( "x=	30	pounds	10	%	Alloy II						<BR>\n" );
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